I have got a new requirement that is we need show workflow operations in 'sub-task' columns. Any one who can give some hints on this? Thanks a lot.
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I get this resolved by adding the below code. It works at jira3.13.5. Thanks Maya for your answering.
final SubTaskColumnLayoutFactory subTaskColumnLayoutFactory = (SubTaskColumnLayoutFactory)ComponentManager.getComponentInstanceOfType(SubTaskColumnLayoutFactory.class); final ColumnLayoutItem workflowLinks = subTaskColumnLayoutFactory.getSubTaskWorkflowLinksColumn(searchUser, currentIssue); layoutBean.getColumns().add(workflowLinks); //make sure here issueObjects is a list of MutableIssue not Issue new IssueTableWebComponent().getHtml(layoutBean, issueObjects, searchResultsPager)
Then you should atleast vote up Maya's answer :)
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This is part of what you need: http://jira.wordpress.com/2008/12/08/showing-custom-fields-in-sub-task-columns/
That will get you the additional columns in the sub-task display.
As for how to display the operations (action button?) there, hopefully someone else has an idea on that. Good luck!
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Thank you very much, Maya. However, maybe I did not speak it clearly. Some things i want to do is adding action buttons on the layout generated by IssueTableWebComponent.getHtml(IssueTableLayoutBean layout, List issues, IssuePager pager), which appeared on the sub-task view page.
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Ah, ok. I haven't done this myself, but the closest thing I can suggest is use of the setShowActionColumn method. http://docs.atlassian.com/jira/5.0-m4/index.html?com/atlassian/jira/web/component/IssueTableLayoutBean.html
public void setShowActionColumn(boolean showActionColumn)
That won't get you the buttons, but it will allow the Actions column controls.
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